What is the answer to 2(1/8)^{1-2x}=16^{x+6} ?

The answer to 2(1/8)^{1-2x}=16^{x+6} is x=13

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2(1/8)^{1-2x}=16^{x+6}

2 (\frac{1}{8})^{1 - 2 x} = 1 6^{x + 6}

x = 13

Solution steps

2 (\frac{1}{8})^{1 - 2 x} = 1 6^{x + 6}

Apply exponent rules

- 3 (1 - 2 x) + 1 = 4 (x + 6)

Solve

- 3 (1 - 2 x) + 1 = 4 (x + 6) : x = 13

x = 13

2 = 2^{x}

8^{x - 4} = 4^{x + 1}

\frac{4 ^{3 x - 1}}{16} = 64

2^{2 x - 1} - 9 (2^{x - 2}) + 1 = 0

2 5^{x} = 12 5^{x - 2}

What is the answer to 2(1/8)^{1-2x}=16^{x+6} ?
The answer to 2(1/8)^{1-2x}=16^{x+6} is x=13
Solve for x: 2(1/8)^{1-2x}=16^{x+6}
The solution is x=13