What is the answer to 2^x*3^{x+1}=10 ?

The answer to 2^x*3^{x+1}=10 is x=(ln(10/3))/(ln(6))

Solve for x: 2^x*3^{x+1}=10

The solution is x=(ln(10/3))/(ln(6))

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2^{x} \cdot 3^{x + 1} = 10

x = \frac{ln ( \frac{10}{3} )}{ln ( 6 )}

Decimal Notation

x = 0.67195 \dots

Solution steps

2^{x} \cdot 3^{x + 1} = 10

Apply exponent rules

x ln (6) = ln (\frac{10}{3})

Solve

x ln (6) = ln (\frac{10}{3}) : x = \frac{ln ( \frac{10}{3} )}{ln ( 6 )}

x = \frac{ln ( \frac{10}{3} )}{ln ( 6 )}

1280 = (5) 4^{(n - 1)}

3^{x - 5} = 81

\frac{15}{1 + 2 e ^{- 0.5 n}} = 7.5

72 = 2^{n} \cdot 3^{2}

2 = (1.06)^{x}

What is the answer to 2^x*3^{x+1}=10 ?
The answer to 2^x*3^{x+1}=10 is x=(ln(10/3))/(ln(6))
Solve for x: 2^x*3^{x+1}=10
The solution is x=(ln(10/3))/(ln(6))