What is (x+5)(x+3)(x-7)<= 0 ?

The solution to (x+5)(x+3)(x-7)<= 0 is x<=-5\lor-3<= x<= 7

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(x+5)(x+3)(x-7)<= 0

(x + 5) (x + 3) (x - 7) \leq 0

x \leq - 5 or - 3 \leq x \leq 7

Interval Notation

(- \infty, - 5] \cup [- 3, 7]

Solution steps

(x + 5) (x + 3) (x - 7) \leq 0

Identify the intervals

x \leq - 5 or - 3 \leq x \leq 7

4 x^{2} - 28 x + 40

- \frac{3}{7} + (- \frac{3}{4})

(1 + 2 i)^{2}

x = \frac{20 \cdot 0.7 \cdot 5 - 0.4 \cdot 19.3}{41.67}

3 x + 6 x = - 81

What is (x+5)(x+3)(x-7)<= 0 ?
The solution to (x+5)(x+3)(x-7)<= 0 is x<=-5\lor-3<= x<= 7