What is the answer to e^{4x}+2e^{2x}+1=0 ?

The answer to e^{4x}+2e^{2x}+1=0 is No Solution for x\in\mathbb{R}

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e^{4x}+2e^{2x}+1=0

e^{4 x} + 2 e^{2 x} + 1 = 0

No Solution for x \in R

Solution steps

e^{4 x} + 2 e^{2 x} + 1 = 0

Apply exponent rules

(e^{x})^{4} + 2 (e^{x})^{2} + 1 = 0

Rewrite the equation with

e^{x} = u

(u)^{4} + 2 (u)^{2} + 1 = 0

Solve

u^{4} + 2 u^{2} + 1 = 0 :

No Solution for

u \in R

No Solution for x \in R

21 = 0.2497 e^{1.2073 x}

g (n) = 7^{n}, g (2)

4^{2 x - 1} = \frac{1}{2}

256 = 4^{x}

1.2 = 3.3 (e^{- \frac{0.3}{x}})

What is the answer to e^{4x}+2e^{2x}+1=0 ?
The answer to e^{4x}+2e^{2x}+1=0 is No Solution for x\in\mathbb{R}