What is the answer to 4^{2x+1}=(0.5)^{3x+2} ?

The answer to 4^{2x+1}=(0.5)^{3x+2} is x=-4/7

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4^{2x+1}=(0.5)^{3x+2}

4^{2 x + 1} = (0.5)^{3 x + 2}

x = - \frac{4}{7}

Decimal Notation

x = - 0.57142 \dots

Solution steps

4^{2 x + 1} = (0.5)^{3 x + 2}

4^{2 x + 1} = (\frac{1}{2})^{3 x + 2}

Apply exponent rules

2 (2 x + 1) = - (3 x + 2)

Solve

2 (2 x + 1) = - (3 x + 2) : x = - \frac{4}{7}

x = - \frac{4}{7}

2^{3 x} \cdot 4^{x + 1} = 64

0.0625 = 0. 5^{x}

20 e^{8 k} = 60

12 5^{x} = 625

1 6^{x - 3} = 2^{- x^{2}}

What is the answer to 4^{2x+1}=(0.5)^{3x+2} ?
The answer to 4^{2x+1}=(0.5)^{3x+2} is x=-4/7
Solve for x: 4^{2x+1}=(0.5)^{3x+2}
The solution is x=-4/7