What is the answer to (4^{x-1})/(2^x)=6 ?

The answer to (4^{x-1})/(2^x)=6 is x=(ln(6))/(ln(2))+2

Solve for x: (4^{x-1})/(2^x)=6

The solution is x=(ln(6))/(ln(2))+2

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\frac{4 ^{x - 1}}{2 ^{x}} = 6

x = \frac{ln ( 6 )}{ln ( 2 )} + 2

Decimal Notation

x = 4.58496 \dots

Solution steps

\frac{4 ^{x - 1}}{2 ^{x}} = 6

Apply exponent rules

(2 (x - 1) - x) ln (2) = ln (6)

Solve

(2 (x - 1) - x) ln (2) = ln (6) : x = \frac{ln ( 6 )}{ln ( 2 )} + 2

x = \frac{ln ( 6 )}{ln ( 2 )} + 2

Verify Solutions:

x = \frac{ln ( 6 )}{ln ( 2 )} + 2

True

The solution is

x = \frac{ln ( 6 )}{ln ( 2 )} + 2

x, f = a^{x} + q

2 = e^{0.015 t}

0.8 = 0. 9^{x}

2^{11 - x} = 2^{x + 1}

e^{- x} - x \cdot e^{- x} = 0

What is the answer to (4^{x-1})/(2^x)=6 ?
The answer to (4^{x-1})/(2^x)=6 is x=(ln(6))/(ln(2))+2
Solve for x: (4^{x-1})/(2^x)=6
The solution is x=(ln(6))/(ln(2))+2