What is the answer to 8^{x+1}*4^{7x}=16^{2x-3} ?

The answer to 8^{x+1}*4^{7x}=16^{2x-3} is x=-5/3

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8^{x+1}*4^{7x}=16^{2x-3}

8^{x + 1} \cdot 4^{7 x} = 1 6^{2 x - 3}

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

8^{x + 1} \cdot 4^{7 x} = 1 6^{2 x - 3}

Apply exponent rules

3 (x + 1) + 14 x = 4 (2 x - 3)

Solve

3 (x + 1) + 14 x = 4 (2 x - 3) : x = - \frac{5}{3}

x = - \frac{5}{3}

4^{x} - 3 \cdot 2^{x + 1} = 16

24 3^{x} = 3

10 + 5 e^{2 x} = 17

4^{2 x + 1} = 6^{x + 2}

3^{x + 4} = 27

What is the answer to 8^{x+1}*4^{7x}=16^{2x-3} ?
The answer to 8^{x+1}*4^{7x}=16^{2x-3} is x=-5/3
Solve for x: 8^{x+1}*4^{7x}=16^{2x-3}
The solution is x=-5/3