What is the answer to 2^x+1+2^x-1=20 ?

The answer to 2^x+1+2^x-1=20 is x=(ln(10))/(ln(2))

Solve for x: 2^x+1+2^x-1=20

The solution is x=(ln(10))/(ln(2))

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2^{x} + 1 + 2^{x} - 1 = 20

x = \frac{ln ( 10 )}{ln ( 2 )}

Decimal Notation

x = 3.32192 \dots

Solution steps

2^{x} + 1 + 2^{x} - 1 = 20

Group like terms

2^{x} + 2^{x} + 1 - 1 = 20

Add similar elements:

2^{x} + 2^{x} = 2 \cdot 2^{x}

2 \cdot 2^{x} + 1 - 1 = 20

1 - 1 = 0

2 \cdot 2^{x} = 20

Divide both sides by

2

2^{x} = 10

Apply exponent rules

x ln (2) = ln (10)

Solve

x ln (2) = ln (10) : x = \frac{ln ( 10 )}{ln ( 2 )}

x = \frac{ln ( 10 )}{ln ( 2 )}

1 0^{x} = 0.000001

3^{x^{2} - 8} = \frac{1}{81}

3^{2 x} - 3^{x + 2} = 3^{x} - 9

2 x e^{x} + e^{x} (x^{2} - 3) = 0

e^{2 x} = 3 e^{- \frac{1}{4} x}

What is the answer to 2^x+1+2^x-1=20 ?
The answer to 2^x+1+2^x-1=20 is x=(ln(10))/(ln(2))
Solve for x: 2^x+1+2^x-1=20
The solution is x=(ln(10))/(ln(2))