What is the answer to 2^x+2^{x+2}+2^{x+3}=208 ?

The answer to 2^x+2^{x+2}+2^{x+3}=208 is x=4

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2^x+2^{x+2}+2^{x+3}=208

2^{x} + 2^{x + 2} + 2^{x + 3} = 208

x = 4

Solution steps

2^{x} + 2^{x + 2} + 2^{x + 3} = 208

Factor

2^{x} + 2^{x + 2} + 2^{x + 3} : 13 \cdot 2^{x}

13 \cdot 2^{x} = 208

Divide both sides by

13

2^{x} = 16

Apply exponent rules

x = 4

n, a = p (1 + r)^{n}

2^{y} = 8

2^{y} = 3

2^{y} = 5

2^{x + 2} - 2^{x - 1} - 2^{x - 2} = 26

What is the answer to 2^x+2^{x+2}+2^{x+3}=208 ?
The answer to 2^x+2^{x+2}+2^{x+3}=208 is x=4
Solve for x: 2^x+2^{x+2}+2^{x+3}=208
The solution is x=4