What is the answer to 4^{-x+4}=5^{9x} ?

The answer to 4^{-x+4}=5^{9x} is x=(8ln(2))/(2ln(2)+9ln(5))

Solve for x: 4^{-x+4}=5^{9x}

The solution is x=(8ln(2))/(2ln(2)+9ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4^{- x + 4} = 5^{9 x}

x = \frac{8 ln ( 2 )}{2 ln ( 2 ) + 9 ln ( 5 )}

Decimal Notation

x = 0.34938 \dots

Solution steps

4^{- x + 4} = 5^{9 x}

Apply exponent rules

(- x + 4) ln (4) = 9 x ln (5)

Solve

(- x + 4) ln (4) = 9 x ln (5) : x = \frac{8 ln ( 2 )}{2 ln ( 2 ) + 9 ln ( 5 )}

x = \frac{8 ln ( 2 )}{2 ln ( 2 ) + 9 ln ( 5 )}

(1.09)^{t} = 4

2 e^{2 x} = e^{- x}

e^{x - 5} = 15

(\frac{1}{2})^{n} = 4^{n + 1}

2^{x} + 4^{x} = 1056

What is the answer to 4^{-x+4}=5^{9x} ?
The answer to 4^{-x+4}=5^{9x} is x=(8ln(2))/(2ln(2)+9ln(5))
Solve for x: 4^{-x+4}=5^{9x}
The solution is x=(8ln(2))/(2ln(2)+9ln(5))