What is the answer to 8^x=sqrt(2)^{2x^2+4} ?

The answer to 8^x=sqrt(2)^{2x^2+4} is x=2,x=1

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8^x=sqrt(2)^{2x^2+4}

8^{x} = 2^{2 x^{2} + 4}

x = 2, x = 1

Solution steps

8^{x} = (2)^{2 x^{2} + 4}

Apply exponent rules

3 x = x^{2} + 2

Solve

3 x = x^{2} + 2 : x = 2, x = 1

x = 2, x = 1

2^{x - 8} = 3

2^{x - 8} = 9

2^{x - 8} = 7

3^{2 x - 3} = 5^{3 x - 1}

7^{x - 2} - 3^{2 x + 1} = 0

What is the answer to 8^x=sqrt(2)^{2x^2+4} ?
The answer to 8^x=sqrt(2)^{2x^2+4} is x=2,x=1
Solve for x: 8^x=sqrt(2)^{2x^2+4}
The solution is x=2,x=1