What is the answer to 5^x=3^{2x-1} ?

The answer to 5^x=3^{2x-1} is x=(ln(3))/(2ln(3)-ln(5))

Solve for x: 5^x=3^{2x-1}

The solution is x=(ln(3))/(2ln(3)-ln(5))

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5^{x} = 3^{2 x - 1}

x = \frac{ln ( 3 )}{2 ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = 1.86906 \dots

Solution steps

5^{x} = 3^{2 x - 1}

Apply exponent rules

x ln (5) = (2 x - 1) ln (3)

Solve

x ln (5) = (2 x - 1) ln (3) : x = \frac{ln ( 3 )}{2 ln ( 3 ) - ln ( 5 )}

x = \frac{ln ( 3 )}{2 ln ( 3 ) - ln ( 5 )}

\frac{x}{8 \cdot 2 ^{5 x - 3}} = 24

12 5^{2 x} = \frac{5 ^{x - 3}}{625}

4782969 = 3^{x}

lo g_{2} (4^{x}) = - 2

(\frac{1}{4})^{x - 1} = 1 6^{x + 2}

What is the answer to 5^x=3^{2x-1} ?
The answer to 5^x=3^{2x-1} is x=(ln(3))/(2ln(3)-ln(5))
Solve for x: 5^x=3^{2x-1}
The solution is x=(ln(3))/(2ln(3)-ln(5))