What is the answer to 2^x=41 ?

The answer to 2^x=41 is x=(ln(41))/(ln(2))

The solution is x=(ln(41))/(ln(2))

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2^x=41

2^{x} = 41

x = \frac{ln ( 41 )}{ln ( 2 )}

Decimal Notation

x = 5.35755 \dots

Solution steps

2^{x} = 41

Apply exponent rules

x ln (2) = ln (41)

Solve

x ln (2) = ln (41) : x = \frac{ln ( 41 )}{ln ( 2 )}

x = \frac{ln ( 41 )}{ln ( 2 )}

73 = 2 5^{x}

2^{x} = 80

2^{x} = 70

2^{x} = 98

\frac{1}{e ^{x}} = e^{x}