What is the answer to 57=21^x ?

The answer to 57=21^x is x=(ln(57))/(ln(21))

The solution is x=(ln(57))/(ln(21))

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57=21^x

57 = 2 1^{x}

x = \frac{ln ( 57 )}{ln ( 21 )}

Decimal Notation

x = 1.32797 \dots

Solution steps

57 = 2 1^{x}

Apply exponent rules

ln (57) = x ln (21)

Solve

ln (57) = x ln (21) : x = \frac{ln ( 57 )}{ln ( 21 )}

x = \frac{ln ( 57 )}{ln ( 21 )}

e^{6 x} = 2

e^{y - 9} = 6

2 e^{\frac{t}{2}} = 0

x, x e^{2 x} = 0

2^{x + 3} = 64