What is the answer to 25^{3x+2}=(1/5)^{2x+5} ?

The answer to 25^{3x+2}=(1/5)^{2x+5} is x=-9/8

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25^{3x+2}=(1/5)^{2x+5}

2 5^{3 x + 2} = (\frac{1}{5})^{2 x + 5}

x = - \frac{9}{8}

Decimal Notation

x = - 1.125

Solution steps

2 5^{3 x + 2} = (\frac{1}{5})^{2 x + 5}

Apply exponent rules

2 (3 x + 2) = - (2 x + 5)

Solve

2 (3 x + 2) = - (2 x + 5) : x = - \frac{9}{8}

x = - \frac{9}{8}

e^{2} = e^{2 x^{2} + 1}

4^{x} = 2^{x} + 6

e^{x - 1} = 12

34.1 \cdot 7.1 1^{x} = 120.28

50000 = 100 \cdot 2^{\frac{x}{3}}

What is the answer to 25^{3x+2}=(1/5)^{2x+5} ?
The answer to 25^{3x+2}=(1/5)^{2x+5} is x=-9/8
Solve for x: 25^{3x+2}=(1/5)^{2x+5}
The solution is x=-9/8