What is the answer to 25^{x+1}=125^{3x-1} ?

The answer to 25^{x+1}=125^{3x-1} is x= 5/7

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25^{x+1}=125^{3x-1}

2 5^{x + 1} = 12 5^{3 x - 1}

x = \frac{5}{7}

Decimal Notation

x = 0.71428 \dots

Solution steps

2 5^{x + 1} = 12 5^{3 x - 1}

Apply exponent rules

2 (x + 1) = 3 (3 x - 1)

Solve

2 (x + 1) = 3 (3 x - 1) : x = \frac{5}{7}

x = \frac{5}{7}

\frac{2}{( 2 ^{x} )} = 29

(1 0^{10})^{x} = 1

x, e^{2 x + 2 y + z} = 0

n, (n a)^{n} = a

5^{2 x} = \frac{1}{625}

What is the answer to 25^{x+1}=125^{3x-1} ?
The answer to 25^{x+1}=125^{3x-1} is x= 5/7
Solve for x: 25^{x+1}=125^{3x-1}
The solution is x= 5/7