What is the answer to 5^{x+1}=2^{3x-1} ?

The answer to 5^{x+1}=2^{3x-1} is x=(ln(10))/(3ln(2)-ln(5))

Solve for x: 5^{x+1}=2^{3x-1}

The solution is x=(ln(10))/(3ln(2)-ln(5))

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5^{x + 1} = 2^{3 x - 1}

x = \frac{ln ( 10 )}{3 ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = 4.89907 \dots

Solution steps

5^{x + 1} = 2^{3 x - 1}

Apply exponent rules

(x + 1) ln (5) = (3 x - 1) ln (2)

Solve

(x + 1) ln (5) = (3 x - 1) ln (2) : x = \frac{ln ( 10 )}{3 ln ( 2 ) - ln ( 5 )}

x = \frac{ln ( 10 )}{3 ln ( 2 ) - ln ( 5 )}

2^{x + 1} = 10

x^{x} = 10

5 \cdot 6^{x} = 12 \cdot 3^{x}

3 (5^{x}) - 200 = 175

2^{4 x} = 2^{3 x - 9}

What is the answer to 5^{x+1}=2^{3x-1} ?
The answer to 5^{x+1}=2^{3x-1} is x=(ln(10))/(3ln(2)-ln(5))
Solve for x: 5^{x+1}=2^{3x-1}
The solution is x=(ln(10))/(3ln(2)-ln(5))