What is the answer to solvefor x,2e^x+3e^{-3x}=0 ?

The answer to solvefor x,2e^x+3e^{-3x}=0 is x=Undefined-ln(2)

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solvefor x,2e^x+3e^{-3x}=0

solve for

x, 2 e^{x} + 3 e^{- 3 x} = 0

x = Undefined - ln (2)

Solution steps

2 e^{x} + 3 e^{- 3 x} = 0

Subtract

3 e^{- 3 x}

from both sides

2 e^{x} + 3 e^{- 3 x} - 3 e^{- 3 x} = 0 - 3 e^{- 3 x}

Simplify

2 e^{x} = - 3 e^{- 3 x}

Apply exponent rules

ln (2) + x = ln (- 3) - 3 x

Solve

ln (2) + x = ln (- 3) - 3 x : x =

Undefined

- ln (2)

x = Undefined - ln (2)

e^{2 t + 2} = 2 e^{2 - t}

2 e^{3 x - 2} + 4 = 16

0 = 2 e^{x} - e^{- 3 x}

9^{x + 1} - 3^{x} = 6534

What is the answer to solvefor x,2e^x+3e^{-3x}=0 ?
The answer to solvefor x,2e^x+3e^{-3x}=0 is x=Undefined-ln(2)