What is the answer to 5^{2x+3}=9^{x-5} ?

The answer to 5^{2x+3}=9^{x-5} is x=(-10ln(3)-3ln(5))/(2(-ln(3)+ln(5)))

Solve for x: 5^{2x+3}=9^{x-5}

The solution is x=(-10ln(3)-3ln(5))/(2(-ln(3)+ln(5)))

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5^{2 x + 3} = 9^{x - 5}

x = \frac{- 10 ln ( 3 ) - 3 ln ( 5 )}{2 ( - ln ( 3 ) + ln ( 5 ) )}

Decimal Notation

x = - 15.47929 \dots

Solution steps

5^{2 x + 3} = 9^{x - 5}

Apply exponent rules

(2 x + 3) ln (5) = (x - 5) ln (9)

Solve

(2 x + 3) ln (5) = (x - 5) ln (9) : x = \frac{- 10 ln ( 3 ) - 3 ln ( 5 )}{2 ( - ln ( 3 ) + ln ( 5 ) )}

x = \frac{- 10 ln ( 3 ) - 3 ln ( 5 )}{2 ( - ln ( 3 ) + ln ( 5 ) )}

2^{2 x + 1} + 2^{x + 2} = 12 - 2^{x}

7 \cdot (\frac{1}{3})^{x} = 63

2^{x} \cdot 3^{x} = 6^{x}

9^{2 x - 1} = 81

2^{16} = 4^{x}

What is the answer to 5^{2x+3}=9^{x-5} ?
The answer to 5^{2x+3}=9^{x-5} is x=(-10ln(3)-3ln(5))/(2(-ln(3)+ln(5)))
Solve for x: 5^{2x+3}=9^{x-5}
The solution is x=(-10ln(3)-3ln(5))/(2(-ln(3)+ln(5)))