What are the solutions to the equation 12y^2-8y+58=0 ?

The solutions to the equation 12y^2-8y+58=0 are y= 1/3+i(sqrt(170))/6 ,y= 1/3-i(sqrt(170))/6

Find the zeros of 12y^2-8y+58=0

The zeros of 12y^2-8y+58=0 are y= 1/3+i(sqrt(170))/6 ,y= 1/3-i(sqrt(170))/6

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12 y^{2} - 8 y + 58 = 0

y = \frac{1}{3} + i \frac{170}{6}, y = \frac{1}{3} - i \frac{170}{6}

Solution steps

12 y^{2} - 8 y + 58 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 12 \cdot 58}{2 \cdot 12}

Simplify

(- 8)^{2} - 4 \cdot 12 \cdot 58 : 4170 i

y_{1, 2} = \frac{- ( - 8 ) \pm 4 170 i}{2 \cdot 12}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 4 170 i}{2 \cdot 12}, y_{2} = \frac{- ( - 8 ) - 4 170 i}{2 \cdot 12}

y = \frac{- ( - 8 ) + 4 170 i}{2 \cdot 12} : \frac{1}{3} + i \frac{170}{6}

y = \frac{- ( - 8 ) - 4 170 i}{2 \cdot 12} : \frac{1}{3} - i \frac{170}{6}

The solutions to the quadratic equation are:

y = \frac{1}{3} + i \frac{170}{6}, y = \frac{1}{3} - i \frac{170}{6}

\frac{x}{6} = \frac{4}{3}

13 + 4 a + 2 a = 3 a + 1

- 3 (n - 4) = 5 - 2 n

4 x^{2} - 100 = 0

∣ x ∣ = 14

What are the solutions to the equation 12y^2-8y+58=0 ?
The solutions to the equation 12y^2-8y+58=0 are y= 1/3+i(sqrt(170))/6 ,y= 1/3-i(sqrt(170))/6
Find the zeros of 12y^2-8y+58=0
The zeros of 12y^2-8y+58=0 are y= 1/3+i(sqrt(170))/6 ,y= 1/3-i(sqrt(170))/6