What is the answer to 2^{2x+1}-2x-6=0 ?

The answer to 2^{2x+1}-2x-6=0 is x=1,x=-(\W_{0}(-\frac{ln(2))/(32))+6ln(2)}{2ln(2)}

Solve for x: 2^{2x+1}-2x-6=0

The solution is x=1,x=-(\W_{0}(-\frac{ln(2))/(32))+6ln(2)}{2ln(2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{2 x + 1} - 2 x - 6 = 0

x = 1, x = - \frac{W _{0} ( - \frac{l n ( 2 )}{32} ) + 6 ln ( 2 )}{2 ln ( 2 )}

Decimal Notation

x = 1, x = - 2.98402 \dots

Solution steps

2^{2 x + 1} - 2 x - 6 = 0

Factor

2^{2 x + 1} - 2 x - 6 : 2 (4^{x} - x - 3)

2 (4^{x} - x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4^{x} - x - 3 = 0

Solve

4^{x} - x - 3 = 0 : x = 1, x = - \frac{W _{0} ( - \frac{l n ( 2 )}{32} ) + 6 ln ( 2 )}{2 ln ( 2 )}

x = 1, x = - \frac{W _{0} ( - \frac{l n ( 2 )}{32} ) + 6 ln ( 2 )}{2 ln ( 2 )}

3^{x - 1} + 3^{x} + 3^{x + 1} = 39

2^{x} \cdot 8^{5 x - 1} = 6 4^{x}

4^{2 x - 7} = 16

2^{2 R - 4} - 5^{2 - R} = 0

4^{2 x} = 5^{2 x - 1}

What is the answer to 2^{2x+1}-2x-6=0 ?
The answer to 2^{2x+1}-2x-6=0 is x=1,x=-(\W_{0}(-\frac{ln(2))/(32))+6ln(2)}{2ln(2)}
Solve for x: 2^{2x+1}-2x-6=0
The solution is x=1,x=-(\W_{0}(-\frac{ln(2))/(32))+6ln(2)}{2ln(2)}