What is the answer to 8^{x+2}=(1/32)^{-5x} ?

The answer to 8^{x+2}=(1/32)^{-5x} is x= 3/11

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8^{x+2}=(1/32)^{-5x}

8^{x + 2} = (\frac{1}{32})^{- 5 x}

x = \frac{3}{11}

Decimal Notation

x = 0.27272 \dots

Solution steps

8^{x + 2} = (\frac{1}{32})^{- 5 x}

Apply exponent rules

3 (x + 2) = 25 x

Solve

3 (x + 2) = 25 x : x = \frac{3}{11}

x = \frac{3}{11}

\frac{1}{4 ^{x}} = \frac{1}{64}

e^{x + 2} = 3^{x}

2 5^{x} - 2 \cdot 5^{x} - 8 = 0

2 7^{x + 2} = 81

e^{2 x} = e^{x + 1}

What is the answer to 8^{x+2}=(1/32)^{-5x} ?
The answer to 8^{x+2}=(1/32)^{-5x} is x= 3/11
Solve for x: 8^{x+2}=(1/32)^{-5x}
The solution is x= 3/11