What is the answer to solvefor b,e^{3b}=2+b ?

The answer to solvefor b,e^{3b}=2+b is b=-(\W_{-1}(-3/(e^6))+6)/3 ,b=-(\W_{0}(-3/(e^6))+6)/3

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solvefor b,e^{3b}=2+b

solve for

b, e^{3 b} = 2 + b

b = - \frac{W _{- 1} ( - \frac{3}{e ^{6}} ) + 6}{3}, b = - \frac{W _{0} ( - \frac{3}{e ^{6}} ) + 6}{3}

Decimal Notation

b = 0.27382 \dots, b = - 1.99750 \dots

Solution steps

e^{3 b} = 2 + b

Prepare

e^{3 b} = 2 + b

for Lambert form:

1 = (2 + b) e^{- 3 b}

Rewrite the equation with

- 3 b - 6 = u

and

b = - \frac{u + 6}{3}

1 = (2 + (- \frac{u + 6}{3})) e^{- 3 (- \frac{u + 6}{3})}

Simplify

1 = e^{u + 6} (2 - \frac{u + 6}{3})

Rewrite

1 = e^{u + 6} (2 - \frac{u + 6}{3})

in Lambert form:

e^{u} u = - \frac{3}{e ^{6}}

Solve

e^{u} u = - \frac{3}{e ^{6}} : u = W_{- 1} (- \frac{3}{e ^{6}}), u = W_{0} (- \frac{3}{e ^{6}})

u = W_{- 1} (- \frac{3}{e ^{6}}), u = W_{0} (- \frac{3}{e ^{6}})

Substitute back

u = - 3 b - 6,

solve for

b

Solve

- 3 b - 6 = W_{- 1} (- \frac{3}{e ^{6}}) : b = - \frac{W _{- 1} ( - \frac{3}{e ^{6}} ) + 6}{3}

Solve

- 3 b - 6 = W_{0} (- \frac{3}{e ^{6}}) : b = - \frac{W _{0} ( - \frac{3}{e ^{6}} ) + 6}{3}

b = - \frac{W _{- 1} ( - \frac{3}{e ^{6}} ) + 6}{3}, b = - \frac{W _{0} ( - \frac{3}{e ^{6}} ) + 6}{3}

2^{x} + \frac{4}{2 ^{x}} = 5

500 \cdot 2^{d} = 50 \cdot 3^{d}

3 e^{- 2 x} = 75

8 1^{2^{x + 7}} = 2^{8^{x - 13}}

1 5^{x} = 20

What is the answer to solvefor b,e^{3b}=2+b ?
The answer to solvefor b,e^{3b}=2+b is b=-(\W_{-1}(-3/(e^6))+6)/3 ,b=-(\W_{0}(-3/(e^6))+6)/3