What is the answer to 2200(1.04)^x=8000 ?

The answer to 2200(1.04)^x=8000 is x=(ln(40/11))/(ln(1.04))

Solve for x: 2200(1.04)^x=8000

The solution is x=(ln(40/11))/(ln(1.04))

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2200 (1.04)^{x} = 8000

x = \frac{ln ( \frac{40}{11} )}{ln ( 1.04 )}

Decimal Notation

x = 32.91587 \dots

Solution steps

2200 (1.04)^{x} = 8000

Divide both sides by

2200

1.0 4^{x} = \frac{40}{11}

Apply exponent rules

x ln (1.04) = ln (\frac{40}{11})

Solve

x ln (1.04) = ln (\frac{40}{11}) : x = \frac{ln ( \frac{40}{11} )}{ln ( 1.04 )}

x = \frac{ln ( \frac{40}{11} )}{ln ( 1.04 )}

5 - e^{x} = 0

9 e^{3 x} = 27

72 9^{- \frac{1}{2} x + 4} = 531.441

\frac{1}{2} (e^{x} - e^{- x}) = - 2 e

4^{- 3 n - 2} \cdot 8 = 1 6^{3 n - 2}

What is the answer to 2200(1.04)^x=8000 ?
The answer to 2200(1.04)^x=8000 is x=(ln(40/11))/(ln(1.04))
Solve for x: 2200(1.04)^x=8000
The solution is x=(ln(40/11))/(ln(1.04))