What is the answer to 4-5^x=0 ?

The answer to 4-5^x=0 is x=(2ln(2))/(ln(5))

The solution is x=(2ln(2))/(ln(5))

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4-5^x=0

4 - 5^{x} = 0

x = \frac{2 ln ( 2 )}{ln ( 5 )}

Decimal Notation

x = 0.86135 \dots

Solution steps

4 - 5^{x} = 0

Add

5^{x}

to both sides

4 - 5^{x} + 5^{x} = 0 + 5^{x}

Simplify

4 = 5^{x}

Apply exponent rules

ln (4) = x ln (5)

Solve

ln (4) = x ln (5) : x = \frac{2 ln ( 2 )}{ln ( 5 )}

x = \frac{2 ln ( 2 )}{ln ( 5 )}

2 7^{x - 1} = 9^{x + 3}

4^{x + 1} - 9 \cdot 2^{x} + 2 = 0

5^{3 x - 9} = 15625

e^{3 l n (x)} = 64

5^{5 x - 1} = 12 5^{x + 3}