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Popular >

2^x=n^2-n-2

Solution

2^{x} = n^{2} - n - 2

Solution

x = \frac{ln ( n ^{2} - n - 2 )}{ln ( 2 )}

Solution steps

2^{x} = n^{2} - n - 2

Apply exponent rules

x ln (2) = ln (n^{2} - n - 2)

Solve

x ln (2) = ln (n^{2} - n - 2) : x = \frac{ln ( n ^{2} - n - 2 )}{ln ( 2 )}

x = \frac{ln ( n ^{2} - n - 2 )}{ln ( 2 )}

Popular Examples

8^{x - 5} = 7

16^{x-1}=8^{x+3}

1 6^{x - 1} = 8^{x + 3}

4^{5x}=4^{2x+9}

4^{5 x} = 4^{2 x + 9}

solvefor y,x^y+z=0 solve for

y, x^{y} + z = 0

solvefor x,4^{x-1}=7^{2x}solve for

x, 4^{x - 1} = 7^{2 x}

Frequently Asked Questions (FAQ)

What is the answer to 2^x=n^2-n-2 ?
The answer to 2^x=n^2-n-2 is x=(ln(n^2-n-2))/(ln(2))