What is the answer to 6(4^x)=5(3^{(2x-3)}) ?

The answer to 6(4^x)=5(3^{(2x-3)}) is x=-(ln(162)-ln(5))/(2(ln(2)-ln(3)))

Solve for x: 6(4^x)=5(3^{(2x-3)})

The solution is x=-(ln(162)-ln(5))/(2(ln(2)-ln(3)))

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6 (4^{x}) = 5 (3^{(2 x - 3)})

x = - \frac{ln ( 162 ) - ln ( 5 )}{2 ( ln ( 2 ) - ln ( 3 ) )}

Decimal Notation

x = 4.28909 \dots

Solution steps

6 (4^{x}) = 5 (3^{(2 x - 3)})

Apply exponent rules

ln (6) + x ln (4) = ln (5) + (2 x - 3) ln (3)

Solve

ln (6) + x ln (4) = ln (5) + (2 x - 3) ln (3) : x = - \frac{ln ( 162 ) - ln ( 5 )}{2 ( ln ( 2 ) - ln ( 3 ) )}

x = - \frac{ln ( 162 ) - ln ( 5 )}{2 ( ln ( 2 ) - ln ( 3 ) )}

5^{x - 2} - 5^{x} = - \frac{24}{125}

ln (1 + 2^{x}) = 2

1 0^{a} = 36.9

3^{x} \cdot 4^{x} = 14 4^{x - 2}

x, e^{x^{2} + x + I n (4)} = 4

What is the answer to 6(4^x)=5(3^{(2x-3)}) ?
The answer to 6(4^x)=5(3^{(2x-3)}) is x=-(ln(162)-ln(5))/(2(ln(2)-ln(3)))
Solve for x: 6(4^x)=5(3^{(2x-3)})
The solution is x=-(ln(162)-ln(5))/(2(ln(2)-ln(3)))