What is the answer to 15=60^{(2ln(2/3)t)} ?

The answer to 15=60^{(2ln(2/3)t)} is t=(ln(15))/(2ln(2/3)ln(60))

Solve for t: 15=60^{(2ln(2/3)t)}

The solution is t=(ln(15))/(2ln(2/3)ln(60))

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15 = 6 0^{(2 l n (\frac{2}{3}) t)}

t = \frac{ln ( 15 )}{2 ln ( \frac{2}{3} ) ln ( 60 )}

Decimal Notation

t = - 0.81562 \dots

Solution steps

15 = 6 0^{(2 l n (\frac{2}{3}) t)}

Apply exponent rules

ln (15) = 2 ln (\frac{2}{3}) t ln (60)

Solve

ln (15) = 2 ln (\frac{2}{3}) t ln (60) : t = \frac{ln ( 15 )}{2 ln ( \frac{2}{3} ) ln ( 60 )}

t = \frac{ln ( 15 )}{2 ln ( \frac{2}{3} ) ln ( 60 )}

6^{x} = 67

6^{x} = 35

\frac{1}{2} - e^{- x} = 0

6^{x} = 10

(a + 3)^{t} = (2 a - 5)^{t}

What is the answer to 15=60^{(2ln(2/3)t)} ?
The answer to 15=60^{(2ln(2/3)t)} is t=(ln(15))/(2ln(2/3)ln(60))
Solve for t: 15=60^{(2ln(2/3)t)}
The solution is t=(ln(15))/(2ln(2/3)ln(60))