What is the answer to 4^{2t}=5^{4t+4} ?

The answer to 4^{2t}=5^{4t+4} is t=(ln(5))/(ln(2)-ln(5))

Solve for t: 4^{2t}=5^{4t+4}

The solution is t=(ln(5))/(ln(2)-ln(5))

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4^{2 t} = 5^{4 t + 4}

t = \frac{ln ( 5 )}{ln ( 2 ) - ln ( 5 )}

Decimal Notation

t = - 1.75647 \dots

Solution steps

4^{2 t} = 5^{4 t + 4}

Apply exponent rules

2 t ln (4) = (4 t + 4) ln (5)

Solve

2 t ln (4) = (4 t + 4) ln (5) : t = \frac{ln ( 5 )}{ln ( 2 ) - ln ( 5 )}

t = \frac{ln ( 5 )}{ln ( 2 ) - ln ( 5 )}

\frac{1}{e ^{4 x}} = e^{- 4 x}

t^{0} = 2 e^{- 50 t} - 70 e^{- 50 t}

0.19 = 0.5 - 0.4 e^{\frac{- 3 t}{25}}

e^{l n (w^{2} + 1)} = 5

\frac{3}{3 ^{- k}} = 927

What is the answer to 4^{2t}=5^{4t+4} ?
The answer to 4^{2t}=5^{4t+4} is t=(ln(5))/(ln(2)-ln(5))
Solve for t: 4^{2t}=5^{4t+4}
The solution is t=(ln(5))/(ln(2)-ln(5))