What is the answer to 19.972=a^{120-h}+k ?

The answer to 19.972=a^{120-h}+k is h=-(ln(19.972-k)-120ln(a))/(ln(a))

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19.972=a^{120-h}+k

19.972 = a^{120 - h} + k

h = - \frac{ln ( 19.972 - k ) - 120 ln ( a )}{ln ( a )}

Solution steps

19.972 = a^{120 - h} + k

Switch sides

a^{120 - h} + k = 19.972

Move

k

to the right side

a^{120 - h} = 19.972 - k

Apply exponent rules

(120 - h) ln (a) = ln (19.972 - k)

Solve

(120 - h) ln (a) = ln (19.972 - k) : h = - \frac{ln ( 19.972 - k ) - 120 ln ( a )}{ln ( a )}

h = - \frac{ln ( 19.972 - k ) - 120 ln ( a )}{ln ( a )}

e^{- 0.1 x + 1} = 1

(7^{3 x})^{3} = 243

2^{x - 1} = \frac{1}{8}

2 5^{x + 2} = 5^{x^{2} + 6 x + 7}

4^{x} - 2^{x} = 2

What is the answer to 19.972=a^{120-h}+k ?
The answer to 19.972=a^{120-h}+k is h=-(ln(19.972-k)-120ln(a))/(ln(a))