What is the answer to 4^{x+2}=8^{-2x} ?

The answer to 4^{x+2}=8^{-2x} is x=-1/2

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4^{x+2}=8^{-2x}

4^{x + 2} = 8^{- 2 x}

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

4^{x + 2} = 8^{- 2 x}

Apply exponent rules

2 (x + 2) = - 6 x

Solve

2 (x + 2) = - 6 x : x = - \frac{1}{2}

x = - \frac{1}{2}

3^{x} e^{4 x} = e^{7}

2^{2 x + 1} = 3 (2^{x}) - 1

2 7^{x} = 8 1^{x}

x = e^{\frac{1}{2} x - 2}

5^{x^{2} - 1} = 1