What is the answer to 10^{x-7}+4=11 ?

The answer to 10^{x-7}+4=11 is x=(ln(7))/(ln(10))+7

Solve for x: 10^{x-7}+4=11

The solution is x=(ln(7))/(ln(10))+7

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1 0^{x - 7} + 4 = 11

x = \frac{ln ( 7 )}{ln ( 10 )} + 7

Decimal Notation

x = 7.84509 \dots

Solution steps

1 0^{x - 7} + 4 = 11

Move

4

to the right side

1 0^{x - 7} = 7

Apply exponent rules

(x - 7) ln (10) = ln (7)

Solve

(x - 7) ln (10) = ln (7) : x = \frac{ln ( 7 )}{ln ( 10 )} + 7

x = \frac{ln ( 7 )}{ln ( 10 )} + 7

e^{x} = x^{e}

2^{x - 3} = 0.5

e^{(- 0.005 t)} = 100

(\frac{1}{8})^{x + 1} = 3 2^{x}

0. 5^{x} = 10

What is the answer to 10^{x-7}+4=11 ?
The answer to 10^{x-7}+4=11 is x=(ln(7))/(ln(10))+7
Solve for x: 10^{x-7}+4=11
The solution is x=(ln(7))/(ln(10))+7