What is the answer to 4*3^{x-2}-1=19 ?

The answer to 4*3^{x-2}-1=19 is x=(ln(5))/(ln(3))+2

Solve for x: 4*3^{x-2}-1=19

The solution is x=(ln(5))/(ln(3))+2

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4 \cdot 3^{x - 2} - 1 = 19

x = \frac{ln ( 5 )}{ln ( 3 )} + 2

Decimal Notation

x = 3.46497 \dots

Solution steps

4 \cdot 3^{x - 2} - 1 = 19

Move

1

to the right side

4 \cdot 3^{x - 2} = 20

Divide both sides by

4

3^{x - 2} = 5

Apply exponent rules

(x - 2) ln (3) = ln (5)

Solve

(x - 2) ln (3) = ln (5) : x = \frac{ln ( 5 )}{ln ( 3 )} + 2

x = \frac{ln ( 5 )}{ln ( 3 )} + 2

8^{n - 1} = 2

(x - 3)^{2 x - 4} = (x - 3)^{x + 3}

(0.1)^{2 x - 4} = 10

3^{30} = 2 7^{y}

2^{x + 1} = 3^{2 x + 1}

What is the answer to 4*3^{x-2}-1=19 ?
The answer to 4*3^{x-2}-1=19 is x=(ln(5))/(ln(3))+2
Solve for x: 4*3^{x-2}-1=19
The solution is x=(ln(5))/(ln(3))+2