What is the answer to 9*10^x-81=0 ?

The answer to 9*10^x-81=0 is x=(2ln(3))/(ln(10))

Solve for x: 9*10^x-81=0

The solution is x=(2ln(3))/(ln(10))

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9 \cdot 1 0^{x} - 81 = 0

x = \frac{2 ln ( 3 )}{ln ( 10 )}

Decimal Notation

x = 0.95424 \dots

Solution steps

9 \cdot 1 0^{x} - 81 = 0

Add

81

to both sides

9 \cdot 1 0^{x} - 81 + 81 = 0 + 81

Simplify

9 \cdot 1 0^{x} = 81

Divide both sides by

9

1 0^{x} = 9

Apply exponent rules

x ln (10) = ln (9)

Solve

x ln (10) = ln (9) : x = \frac{2 ln ( 3 )}{ln ( 10 )}

x = \frac{2 ln ( 3 )}{ln ( 10 )}

(x + 2)^{3 x - 2} = (x + 2)^{x - 4}

x = 2 e^{- x}

\frac{1}{100} = 1 0^{x}

2^{x} + 2^{x} (x + 2) = 0

t, e^{2 t} - 3 e^{t} = 0

What is the answer to 9*10^x-81=0 ?
The answer to 9*10^x-81=0 is x=(2ln(3))/(ln(10))
Solve for x: 9*10^x-81=0
The solution is x=(2ln(3))/(ln(10))