What is the answer to 2^{x^2-4}=128 ?

The answer to 2^{x^2-4}=128 is x=sqrt(11),x=-sqrt(11)

Solve for x: 2^{x^2-4}=128

The solution is x=sqrt(11),x=-sqrt(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x^{2} - 4} = 128

x = 11, x = - 11

Decimal Notation

x = 3.31662 \dots, x = - 3.31662 \dots

Solution steps

2^{x^{2} - 4} = 128

Apply exponent rules

x^{2} - 4 = 7

Solve

x^{2} - 4 = 7 : x = 11, x = - 11

x = 11, x = - 11

8 \cdot 1 0^{n + 4} = 42

3^{2 x - 1} = 2100

10.5 = 15 (1 - e^{- (k) 40})

20 e^{2 x} - 40 e^{- x} = 0

1 0^{3 x} = 100000

What is the answer to 2^{x^2-4}=128 ?
The answer to 2^{x^2-4}=128 is x=sqrt(11),x=-sqrt(11)
Solve for x: 2^{x^2-4}=128
The solution is x=sqrt(11),x=-sqrt(11)