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Popular >

solvefor x,-f=2^x+1

Solution

solve for

x, - f = 2^{x} + 1

Solution

x = \frac{ln ( - f - 1 )}{ln ( 2 )}

Solution steps

- f = 2^{x} + 1

Switch sides

2^{x} + 1 = - f

Move

1

to the right side

2^{x} = - f - 1

Apply exponent rules

x ln (2) = ln (- f - 1)

Solve

x ln (2) = ln (- f - 1) : x = \frac{ln ( - f - 1 )}{ln ( 2 )}

x = \frac{ln ( - f - 1 )}{ln ( 2 )}

Popular Examples

2^x+2^{x+2}= 9/2

2^{x} + 2^{x + 2} = \frac{9}{2}

(3^{3m})/(3^{m+1)}=243

\frac{3 ^{3 m}}{3 ^{m + 1}} = 243

6 (9^{x}) + 3^{x} - 2 = 0

3 \cdot 4 9^{x} = 3

e^{r + 4} + 6 = 29

Frequently Asked Questions (FAQ)

What is the answer to solvefor x,-f=2^x+1 ?
The answer to solvefor x,-f=2^x+1 is x=(ln(-f-1))/(ln(2))