What is the answer to 3^{2x+1}-3^{x+2}=-6 ?

The answer to 3^{2x+1}-3^{x+2}=-6 is x=(ln(2))/(ln(3)),x=0

Solve for x: 3^{2x+1}-3^{x+2}=-6

The solution is x=(ln(2))/(ln(3)),x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{2 x + 1} - 3^{x + 2} = - 6

x = \frac{ln ( 2 )}{ln ( 3 )}, x = 0

Decimal Notation

x = 0.63092 \dots, x = 0

Solution steps

3^{2 x + 1} - 3^{x + 2} = - 6

Apply exponent rules

(3^{x})^{2} \cdot 3^{1} - 3^{x} \cdot 3^{2} = - 6

Rewrite the equation with

3^{x} = u

(u)^{2} \cdot 3^{1} - u \cdot 3^{2} = - 6

Solve

u^{2} \cdot 3^{1} - u \cdot 3^{2} = - 6 : u = 2, u = 1

u = 2, u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 2 : x = \frac{ln ( 2 )}{ln ( 3 )}

Solve

3^{x} = 1 : x = 0

x = \frac{ln ( 2 )}{ln ( 3 )}, x = 0

4 9^{- 5 x + 2} = 1680 7^{x - 14}

x, 9^{1 - 7 x} = 24 3^{x - 11}

(3^{4})^{3} = 2 7^{x}

\frac{4 ^{2 x}}{4 ^{x}} = 64

2^{x} - 2^{x - 3} = 14

What is the answer to 3^{2x+1}-3^{x+2}=-6 ?
The answer to 3^{2x+1}-3^{x+2}=-6 is x=(ln(2))/(ln(3)),x=0
Solve for x: 3^{2x+1}-3^{x+2}=-6
The solution is x=(ln(2))/(ln(3)),x=0