What is the answer to 5^{x+2}=4^{2x-2} ?

The answer to 5^{x+2}=4^{2x-2} is x=(2ln(20))/(4ln(2)-ln(5))

Solve for x: 5^{x+2}=4^{2x-2}

The solution is x=(2ln(20))/(4ln(2)-ln(5))

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5^{x + 2} = 4^{2 x - 2}

x = \frac{2 ln ( 20 )}{4 ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = 5.15106 \dots

Solution steps

5^{x + 2} = 4^{2 x - 2}

Apply exponent rules

(x + 2) ln (5) = (2 x - 2) ln (4)

Solve

(x + 2) ln (5) = (2 x - 2) ln (4) : x = \frac{2 ln ( 20 )}{4 ln ( 2 ) - ln ( 5 )}

x = \frac{2 ln ( 20 )}{4 ln ( 2 ) - ln ( 5 )}

e^{e} - 12 e^{- x} - 1 = 0

5 = 10 (0.8)^{x}

2 7^{x} = 9^{x - 4}

5. 3^{x} + 2. 3^{3} = 63

4 e^{2 x} = 81 - 5 e^{2 x}

What is the answer to 5^{x+2}=4^{2x-2} ?
The answer to 5^{x+2}=4^{2x-2} is x=(2ln(20))/(4ln(2)-ln(5))
Solve for x: 5^{x+2}=4^{2x-2}
The solution is x=(2ln(20))/(4ln(2)-ln(5))