What is the answer to 3^x-1+3^x+1=90 ?

The answer to 3^x-1+3^x+1=90 is x=(ln(45))/(ln(3))

Solve for x: 3^x-1+3^x+1=90

The solution is x=(ln(45))/(ln(3))

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3^{x} - 1 + 3^{x} + 1 = 90

x = \frac{ln ( 45 )}{ln ( 3 )}

Decimal Notation

x = 3.46497 \dots

Solution steps

3^{x} - 1 + 3^{x} + 1 = 90

Group like terms

3^{x} + 3^{x} - 1 + 1 = 90

Add similar elements:

3^{x} + 3^{x} = 2 \cdot 3^{x}

2 \cdot 3^{x} - 1 + 1 = 90

- 1 + 1 = 0

2 \cdot 3^{x} = 90

Divide both sides by

2

3^{x} = 45

Apply exponent rules

x ln (3) = ln (45)

Solve

x ln (3) = ln (45) : x = \frac{ln ( 45 )}{ln ( 3 )}

x = \frac{ln ( 45 )}{ln ( 3 )}

k = 100 e^{- t l n (5)}

1 0^{6 x - 5} = 8^{6 x - 2}

e^{- x} + 2 = x

N = N_{0} e^{λ \cdot t}

2^{- x} = x - 9

What is the answer to 3^x-1+3^x+1=90 ?
The answer to 3^x-1+3^x+1=90 is x=(ln(45))/(ln(3))
Solve for x: 3^x-1+3^x+1=90
The solution is x=(ln(45))/(ln(3))