What is the answer to 4^x=(2^x)^2 ?

The answer to 4^x=(2^x)^2 is True for all x

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4^x=(2^x)^2

4^{x} = (2^{x})^{2}

True for all x

Solution steps

4^{x} = (2^{x})^{2}

Apply exponent rules

2 x = x \cdot 2

Solve

2 x = x \cdot 2 :

True for all

x

True for all x

2^{(x)} + 4 x + 12 = 0

e^{- x} + 3 = 0

3 6^{\frac{1}{2} - 4 x} = 6

2^{5} + 2^{x - 1} = 2^{x}

3^{2 - x} + 3^{3 - x} = 12