What is the answer to 9^{5-3x}=(1/3)^{x-1} ?

The answer to 9^{5-3x}=(1/3)^{x-1} is x= 9/5

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9^{5-3x}=(1/3)^{x-1}

9^{5 - 3 x} = (\frac{1}{3})^{x - 1}

x = \frac{9}{5}

Decimal Notation

x = 1.8

Solution steps

9^{5 - 3 x} = (\frac{1}{3})^{x - 1}

Apply exponent rules

2 (5 - 3 x) = - (x - 1)

Solve

2 (5 - 3 x) = - (x - 1) : x = \frac{9}{5}

x = \frac{9}{5}

2 5^{a - 3} = 125

5 (5^{2 x}) + 14 (5^{x}) - 3 = 0

2 = 1.062 5^{t}

2^{x} = 2.6

3^{x} = 343

What is the answer to 9^{5-3x}=(1/3)^{x-1} ?
The answer to 9^{5-3x}=(1/3)^{x-1} is x= 9/5
Solve for x: 9^{5-3x}=(1/3)^{x-1}
The solution is x= 9/5