What are the solutions to the equation y^2-2y-8=7 ?

The solutions to the equation y^2-2y-8=7 are y=5,y=-3

Find the zeros of y^2-2y-8=7

The zeros of y^2-2y-8=7 are y=5,y=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 2 y - 8 = 7

y = 5, y = - 3

Solution steps

y^{2} - 2 y - 8 = 7

Move

7

to the left side

y^{2} - 2 y - 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

y_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

y = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

y = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

y = 5, y = - 3

\frac{1}{2} 3 x + \frac{2}{3} > \frac{5}{6}

2 y + 2 = 16

10 t - 24 = 21 - 10 t

- 5 (x - 1) \geq 10

\frac{2}{3 - 2}

What are the solutions to the equation y^2-2y-8=7 ?
The solutions to the equation y^2-2y-8=7 are y=5,y=-3
Find the zeros of y^2-2y-8=7
The zeros of y^2-2y-8=7 are y=5,y=-3