What is the answer to 2^{x+1}+2^{x+2}+2^{x+3}=224 ?

The answer to 2^{x+1}+2^{x+2}+2^{x+3}=224 is x=4

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2^{x+1}+2^{x+2}+2^{x+3}=224

2^{x + 1} + 2^{x + 2} + 2^{x + 3} = 224

x = 4

Solution steps

2^{x + 1} + 2^{x + 2} + 2^{x + 3} = 224

Factor

2^{x + 1} + 2^{x + 2} + 2^{x + 3} : 7 \cdot 2^{x + 1}

7 \cdot 2^{x + 1} = 224

Divide both sides by

7

2^{x + 1} = 32

Apply exponent rules

x + 1 = 5

Solve

x + 1 = 5 : x = 4

x = 4

3^{x} = 78

2^{- x^{2}} = 5

6^{3 x - 7} = 3 6^{x - 1}

3^{x} = 29

5 e^{- 0.002 x} = 140

What is the answer to 2^{x+1}+2^{x+2}+2^{x+3}=224 ?
The answer to 2^{x+1}+2^{x+2}+2^{x+3}=224 is x=4
Solve for x: 2^{x+1}+2^{x+2}+2^{x+3}=224
The solution is x=4