What is the answer to 4^{1+x}+4^{1-x}=10 ?

The answer to 4^{1+x}+4^{1-x}=10 is x= 1/2 ,x=-1/2

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4^{1+x}+4^{1-x}=10

4^{1 + x} + 4^{1 - x} = 10

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.5, x = - 0.5

Solution steps

4^{1 + x} + 4^{1 - x} = 10

Apply exponent rules

4^{x} \cdot 4^{1} + (4^{x})^{- 1} \cdot 4^{1} = 10

Rewrite the equation with

4^{x} = u

u \cdot 4^{1} + (u)^{- 1} \cdot 4^{1} = 10

Solve

u \cdot 4^{1} + u^{- 1} \cdot 4^{1} = 10 : u = 2, u = \frac{1}{2}

u = 2, u = \frac{1}{2}

Substitute back

u = 4^{x},

solve for

x

Solve

4^{x} = 2 : x = \frac{1}{2}

Solve

4^{x} = \frac{1}{2} : x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

8 = 80 (0.1)^{x}

e^{n - 4} + 4 = 82

50 = 10 + 60 e^{0.5 k}

4 = 20 (1 - 0.06)^{x}

5^{100} - 5^{99} = 5^{x} \cdot 4

What is the answer to 4^{1+x}+4^{1-x}=10 ?
The answer to 4^{1+x}+4^{1-x}=10 is x= 1/2 ,x=-1/2
Solve for x: 4^{1+x}+4^{1-x}=10
The solution is x= 1/2 ,x=-1/2