What is the answer to 3^{(5-x)}=2^{(5+x)} ?

The answer to 3^{(5-x)}=2^{(5+x)} is x=(5ln(3)-5ln(2))/(ln(6))

Solve for x: 3^{(5-x)}=2^{(5+x)}

The solution is x=(5ln(3)-5ln(2))/(ln(6))

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3^{(5 - x)} = 2^{(5 + x)}

x = \frac{5 ln ( 3 ) - 5 ln ( 2 )}{ln ( 6 )}

Decimal Notation

x = 1.13147 \dots

Solution steps

3^{(5 - x)} = 2^{(5 + x)}

Apply exponent rules

(5 - x) ln (3) = (5 + x) ln (2)

Solve

(5 - x) ln (3) = (5 + x) ln (2) : x = \frac{5 ln ( 3 ) - 5 ln ( 2 )}{ln ( 6 )}

x = \frac{5 ln ( 3 ) - 5 ln ( 2 )}{ln ( 6 )}

e^{6 - 4 x} = 3

e^{6 - 4 x} = 2

4^{x} - 10 (4^{- x}) = 3

5^{2 x^{2} + 3 x - 2} = 1

2^{x - 5} = 6^{x}

What is the answer to 3^{(5-x)}=2^{(5+x)} ?
The answer to 3^{(5-x)}=2^{(5+x)} is x=(5ln(3)-5ln(2))/(ln(6))
Solve for x: 3^{(5-x)}=2^{(5+x)}
The solution is x=(5ln(3)-5ln(2))/(ln(6))