What is the answer to 2^x*3^x=81 ?

The answer to 2^x*3^x=81 is x=(4ln(3))/(ln(6))

Solve for x: 2^x*3^x=81

The solution is x=(4ln(3))/(ln(6))

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2^{x} \cdot 3^{x} = 81

x = \frac{4 ln ( 3 )}{ln ( 6 )}

Decimal Notation

x = 2.45258 \dots

Solution steps

2^{x} \cdot 3^{x} = 81

Apply exponent rules

x ln (6) = ln (81)

Solve

x ln (6) = ln (81) : x = \frac{4 ln ( 3 )}{ln ( 6 )}

x = \frac{4 ln ( 3 )}{ln ( 6 )}

3^{x + 3} + \frac{1}{3 ^{x}} - 28 = 0

75 e^{- 0.1 (t)} = 3

20 x + 1 = 3^{x}

(\frac{1}{5})^{x} = 625

5 (2^{2 p + 1}) - 17 (2^{p + 3}) = 0

What is the answer to 2^x*3^x=81 ?
The answer to 2^x*3^x=81 is x=(4ln(3))/(ln(6))
Solve for x: 2^x*3^x=81
The solution is x=(4ln(3))/(ln(6))