What is the answer to (64^{2x+1})/(256)=16^{x-2} ?

The answer to (64^{2x+1})/(256)=16^{x-2} is x=-3/4

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(64^{2x+1})/(256)=16^{x-2}

\frac{6 4 ^{2 x + 1}}{256} = 1 6^{x - 2}

x = - \frac{3}{4}

Decimal Notation

x = - 0.75

Solution steps

\frac{6 4 ^{2 x + 1}}{256} = 1 6^{x - 2}

Multiply both sides by

256

\frac{6 4 ^{2 x + 1}}{256} \cdot 256 = 1 6^{x - 2} \cdot 256

Simplify

6 4^{2 x + 1} = 1 6^{x - 2} \cdot 256

Apply exponent rules

3 (2 x + 1) = 2 (x - 2) + 4

Solve

3 (2 x + 1) = 2 (x - 2) + 4 : x = - \frac{3}{4}

x = - \frac{3}{4}

8^{2 x + 1} = 2^{x}

16 = 2^{e}

4^{n} = 64

2^{6} = 2^{(6 - x) (5 - x)}

(3)^{2 x + 1} + 3^{2} = 28 (3^{x})

What is the answer to (64^{2x+1})/(256)=16^{x-2} ?
The answer to (64^{2x+1})/(256)=16^{x-2} is x=-3/4
Solve for x: (64^{2x+1})/(256)=16^{x-2}
The solution is x=-3/4