What is the answer to 2*3^x+5=17 ?

The answer to 2*3^x+5=17 is x=(ln(6))/(ln(3))

Solve for x: 2*3^x+5=17

The solution is x=(ln(6))/(ln(3))

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2 \cdot 3^{x} + 5 = 17

x = \frac{ln ( 6 )}{ln ( 3 )}

Decimal Notation

x = 1.63092 \dots

Solution steps

2 \cdot 3^{x} + 5 = 17

Move

5

to the right side

2 \cdot 3^{x} = 12

Divide both sides by

2

3^{x} = 6

Apply exponent rules

x ln (3) = ln (6)

Solve

x ln (3) = ln (6) : x = \frac{ln ( 6 )}{ln ( 3 )}

x = \frac{ln ( 6 )}{ln ( 3 )}

300 \cdot 1 0^{x} = 20 \cdot 2 0^{x}

\frac{1}{4} = e^{- x}

3^{x + 5} = \frac{1}{27}

y, x = e^{y} - 2

(4)^{2 x - 3} = (8)^{- x}

What is the answer to 2*3^x+5=17 ?
The answer to 2*3^x+5=17 is x=(ln(6))/(ln(3))
Solve for x: 2*3^x+5=17
The solution is x=(ln(6))/(ln(3))