What is the answer to e^{mx}(m^2-5m+6)=0 ?

The answer to e^{mx}(m^2-5m+6)=0 is No Solution for x\in\mathbb{R}

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e^{mx}(m^2-5m+6)=0

e^{m x} (m^{2} - 5 m + 6) = 0

No Solution for x \in R

Solution steps

e^{m x} (m^{2} - 5 m + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

e^{m x} = 0

Solve

e^{m x} = 0 :

No Solution for

x \in R

No Solution for x \in R

x, 5^{x} = 31

2^{x} + 3 \cdot 4^{2} = 128

(8^{x}) = e^{x + 7}

e^{l n (2 x)} = 12

2^{x} = 2^{1 - x}

What is the answer to e^{mx}(m^2-5m+6)=0 ?
The answer to e^{mx}(m^2-5m+6)=0 is No Solution for x\in\mathbb{R}