What is the answer to 4^{7x-2}=17^{x+1} ?

The answer to 4^{7x-2}=17^{x+1} is x=(ln(272))/(14ln(2)-ln(17))

Solve for x: 4^{7x-2}=17^{x+1}

The solution is x=(ln(272))/(14ln(2)-ln(17))

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4^{7 x - 2} = 1 7^{x + 1}

x = \frac{ln ( 272 )}{14 ln ( 2 ) - ln ( 17 )}

Decimal Notation

x = 0.81588 \dots

Solution steps

4^{7 x - 2} = 1 7^{x + 1}

Apply exponent rules

(7 x - 2) ln (4) = (x + 1) ln (17)

Solve

(7 x - 2) ln (4) = (x + 1) ln (17) : x = \frac{ln ( 272 )}{14 ln ( 2 ) - ln ( 17 )}

x = \frac{ln ( 272 )}{14 ln ( 2 ) - ln ( 17 )}

6^{x} = 3 6^{3}

5^{2 x + 3} = 6^{x - 1}

3^{x} = 3^{- x}

2^{3 x + 4} = 10

0.51 = 1 - \frac{1}{1 1 ^{x - 1}}

What is the answer to 4^{7x-2}=17^{x+1} ?
The answer to 4^{7x-2}=17^{x+1} is x=(ln(272))/(14ln(2)-ln(17))
Solve for x: 4^{7x-2}=17^{x+1}
The solution is x=(ln(272))/(14ln(2)-ln(17))